Question

4х + 3y = 12
х = 5y - 20


Solve the system by substitution

Answer 1

y=4 and x=0

Explanation:

4(5y-20)+3y=12

20y-80+3y=12

23y-80=12

23y=92

y=4

Substitute y as 4 to get x.

Answer 2

y=4

x=0

Explanation:

4x + 3y = 12

X - 5y =-20

Multiply second equation by 4

4x + 3y = 12

4x - 20y = - 80

Subtract

23y = 92

y = 92/23

y =4

Put the value in first equation

4x + 12 =12

So 4x = 0

Therefore x= 0