Question

We have a photon with the wavelength of 605 nm. What is the frequency of this
photon?

Answer 1

ν=4.96x10^14 Hz

Step-by-step explanation:

c=λν

λ=wavelength

ν=frequency

in this problem:

c=3x10^8

λ=605x10^-9

so ν=c/λ

v=(3x10^8)/(605x10^-9)

v=4.96x10^14

please give thanks :)

Answer 2

Step-by-step explanation:

Speed of light = Wavelength x Frequency.

605 nm x Frequency = 3x10^8 m/s

6.05 x 10^-7 m x Frequency = 3x10^8 m/s

Frequency = 4.96 x 10^14 Hz