Answer:
Mass of MgF₂ formed = 40.5 g
Step-by-step explanation:
Given data:
Mass of NaF = 55 g
Mass of MgF₂ formed = ?
Solution:
Chemical equation:
2NaF + Mg → MgF₂ + 2Na
Number of moles of NaF:
Number of moles = mass/molar mass
Number of moles = 55 g / 41.98 g/mol
Number of moles = 1.3 mol
now we will compare the moles of sodium fluoride with magnesium fluoride.
NaF : MgF₂
2 : 1
1.3 : 1/2×1.3 = 0.65 mol
Mass of magnesium fluoride:
Mass = number of moles × molar mass
Mass = 0.65 mol × 62.3 g/mol
Mass = 40.5 g