We are given:
The line passes through (2,-3)
Slope of the line = 4
Finding the equation of the line:
We know that the general form of the slope-intercept form is:
y = mx + b [where m is the slope and b is the y-intercept]
y = 4x + b [since slope = 4]
Finding the y-intercept:
Now, we are given that the line passes through the points: (2,-3)
which can be written as: x = 2 and y = -3
Since the line passes through these points, these values must satisfy the equation
So,
y = 4x + b
-3 = 2(4) + b
-3 = 8 + b
b = -11 [subtracting 8 from both sides]
Hence, the y-intercept is -11
Equation of the line:
We wrote the equation of the line as:
y = 4x + b (where b is the y-intercept)
now that we know the value of b,
y = 4x - 11
Therefore, the equation of the line is: y = 4x - 11