Question

What is the velocity of v2 if m1=82kg v1= 25 m/s m2=60kg?

Answer 1

Given :

`m_1 = 82 \ kg\\\\v_1 = 257 m/s\\\\m_2 = 60 kg`

Let, us assume that momentum is conserved during the process.

To Find :

The velocity
`v_2` .

Solution :

Applying conservation of momentum :

Initial momentum = Final momentum

`m_1v_1 = m_2v_2\\\\82* 257=60* v_2\\\\v_2 = (82* 257)/(60)\ m/s\\\\v_2 = 351.23\ m/s`

Hence, this is the required solution.