Question

How many moles are equal to 12.65 grams of Al2(SO4)3?

Answer 1

0.03697 mol Al₂(SO₄)₃

General Formulas and Concepts:

Chemistry - Atomic Structure

• Reading a Periodic Table
• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

12.65 g Al₂(SO₄)₃

Step 2: Identify Conversions

Molar Mass of Al - 26.98 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Al₂(SO₄)₃ - 2(26.98) + 3(32.07) + 12(16.00) = 342.17 g/mol

Step 3: Convert

`12.65 \ g \ Al_2(SO_4)_3((1 \ mol \ Al_2(SO_4)_3)/(342.17 \ g \ Al_2(SO_4)_3) )` = 0.03697 mol Al₂(SO₄)₃

Step 4: Check

We are given 4 sig figs. Follow sig fig rules and round.

We already have 4 sig figs in the final answer, so no need to round.