Answer:
cm --- (a)
cm --- (c)
Explanation:
Only (a) & (c) are clear enough to be solved. Others are not properly presented.
Use the following explanations of (a) & (c) to answer others.
![a.\ Area = 100cm^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/hio0qgaeojoo6lwtm0v4l0zjna3jik1r8q.png)
Area is calculated as:
![Area = \pi r^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/d8idhdkbvny3nuf23y6dswar31w3y3ic8z.png)
Substitute 100 for Area
![100 = \pi r^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/pdaapzsurxw9vydpgcxo876ad6wj7c3p28.png)
Take π as 3.14. So, the expression become
![100 = 3.14 r^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/uk68sgmptmrsrtoejm8v9pjrlwgiu5mcr7.png)
Divide both sides by 3.14
![(100)/(3.14) = (3.14 r^2)/(3.14)](https://img.qammunity.org/2021/formulas/mathematics/high-school/xkd7d2s5ldwpaibi3d7bjpbsauf6hbnfku.png)
![(100)/(3.14) = r^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/c81d4ljvh1n1lly3y6gzusdwe5wo52gj0y.png)
![r^2 = (100)/(3.14)](https://img.qammunity.org/2021/formulas/mathematics/high-school/brmr7qh6d6vk35bf64mcshoxa1y6yzlvon.png)
![r^2 = 31.847133758](https://img.qammunity.org/2021/formulas/mathematics/high-school/sbml929bnfhiuh53ns2ng4av18g0lo04pp.png)
Solve for r
![r = \sqrt{31.847133758](https://img.qammunity.org/2021/formulas/mathematics/high-school/dfdb9ukoaxyqnfhb6rcvqx5498b5uowfdh.png)
![r = 5.64](https://img.qammunity.org/2021/formulas/mathematics/high-school/vak4a4iuxvm003kf92pqa4jfp61fmq393t.png)
But diameter = 2 * radius
So:
![Diameter = 2 * 5.64](https://img.qammunity.org/2021/formulas/mathematics/high-school/mflw5htlo4p26ha4fzlwkbgtzxkvbflg20.png)
![Diameter = 11.28](https://img.qammunity.org/2021/formulas/mathematics/high-school/mjj5guxohlls4dgnfgztmbn3q92prr1iza.png)
![a.\ Area = 400cm^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/4trk8qh4sllz8c8gdb05u39s0fpib3wt9t.png)
Area is calculated as:
![Area = \pi r^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/d8idhdkbvny3nuf23y6dswar31w3y3ic8z.png)
Substitute 400 for Area
![400 = \pi r^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/e75ebfj65ezwak8gf2jmbvwk0zb2lxke7q.png)
![400 = 3.14 r^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/4p9uf8kui0a3zfo1iyduzejqorayweokaz.png)
Divide both sides by 3.14
![(400)/(3.14) = (3.14 r^2)/(3.14)](https://img.qammunity.org/2021/formulas/mathematics/high-school/9gqgjt6m9jzfx2h1sb232o7cuuv9evegg1.png)
![(400)/(3.14) = r^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/yuq5ibzprkda98jy3msb97wy7qoat9cgz1.png)
![r^2 = (100)/(3.14)](https://img.qammunity.org/2021/formulas/mathematics/high-school/brmr7qh6d6vk35bf64mcshoxa1y6yzlvon.png)
![r^2 = 127.388535032](https://img.qammunity.org/2021/formulas/mathematics/high-school/7f7xt2zub9oeao8rysk6pzdzurkgd7em6k.png)
Solve for r
![r = \sqrt{127.388535032](https://img.qammunity.org/2021/formulas/mathematics/high-school/49c8z46deszgwns07si8u7378b3m0yzlvu.png)
![r = 11.29](https://img.qammunity.org/2021/formulas/mathematics/high-school/25vhtb9emm1ej87rp2xgrd7p8mrkqu4amj.png)
But diameter = 2 * radius
So:
![Diameter = 2 * 11.29](https://img.qammunity.org/2021/formulas/mathematics/high-school/9r1xg8sfjlzzxa63f57w0zazs0h4dwjdl0.png)
![Diameter =22,58](https://img.qammunity.org/2021/formulas/mathematics/high-school/z1vddqquz9rajzrw68pq46fydf0r7mxpp8.png)