Answer:
49% and 30% respectively
Explanation:
Step one:
Given data
Principal = Rs. 4,200
Final Amount= Rs. 9282 respectively
time = 2 years and
time = 4 years
Required
The rate of interest for 2 and 4 years
Step two:
the compound interest formula is
A= P(1+r)^t
for 2 years
Substitute
![9282= 4200(1+r)^2\\\\9282/4200= (1+r)^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/afwclgm940mh4h46gyz1ss5gh2gw5qgwef.png)
![1+r= \sqrt{(9282)/( 4200) }\\\\1+r= √(2.21) \\\\1+r= 1.49\\\\r=1.49-1\\\\r= 0.49\\\\](https://img.qammunity.org/2021/formulas/mathematics/high-school/b6kyesxki3qwo3xieecsxgtku7jmh6hz5m.png)
the rate is 49%
For 4 years we have
![9282= 4200(1+r)^4\\\\9282/4200= (1+r)^4](https://img.qammunity.org/2021/formulas/mathematics/high-school/uw4ose1jq0v4kxurmu1h0cv0ld1v5t9bgc.png)
![1+r= \sqrt[4]{(9282)/(4500) } \\\\1+r=\sqrt[4]{2.21} \\\\1+r= 1.30\\\\r=1.30-1\\\\r= 0.30\\\\](https://img.qammunity.org/2021/formulas/mathematics/high-school/gavpkzqnab3v74seupx4kfr86nq4u24k63.png)
the rate is 30%