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an object is 40M below the surface of sea water of density 1020 kg/m3 calculate the pressure difference

an object is 40M below the surface of sea water of density 1020 kg/m3 calculate the-example-1
User Ebpa
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1 Answer

1 vote

Answer:

P = 400248 [Pa]

Step-by-step explanation:

We can calculate the hydrostatic pressure exerted by a column of liquid by means of the following equation.


P=Ro*g*h

where:

Ro = density = 1020 [kg/m³]

g = gravity acceleration = 9.81 [m/s²]

h = depth = 40 [m]

Therefore:


P=1020*9.81*40\\P=400248 [Pa]

User Victorio Berra
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