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Solve using the quadratic formula: 2n^2= 6n - 2

User Jayeff
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1 Answer

2 votes

Answer:


n_1=(3 + 1√(5) )/2\\\\n_2=(3 - 1√(5) )/2

Explanation:


2n^2= 6n - 2\\\\2n^2-6n+2=0\\\\a=2\\\\b=-6\\\\c=2


n=(-b \pm √(b^2-4ac) )/2a\\\\n=(-(-6) \pm √((-6)^2-4(2)(2)) )/2(2)\\\\n=(6 \pm √(36-16) )/4\\\\n=(6 \pm √(20) )/4\\\\n=(6 \pm 2√(5) )/4\\\\n=(3 \pm 1√(5) )/2\\\\n_1=(3 + 1√(5) )/2\\\\n_2=(3 - 1√(5) )/2

User Alcedine
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