Question

What is the intensity of 60dB sound?​

Answer 1

The intensity of the sound in W/m² is 1 x 10⁻⁶ W/m².

Step-by-step explanation:

Given;

intensity of the sound level, dB = 60 dB

The intensity of the sound in W/m² is calculated as;

`dB = 10 Log[(I)/(I_o) ]\\\\`

where;

I₀ is threshold of hearing = 1 x 10⁻¹² W/m²

I is intensity of the sound in W/m²

Substitute the given values and for I;

`dB = 10 Log[(I)/(I_o) ]\\\\60 = 10 Log[(I)/(I_o) ]\\\\6 = Log[(I)/(I_o) ]\\\\10^6 = (I)/(I_o) \\\\I = 10^6 \ * \ I_o\\\\I = 10^6 \ * \ 1^(-12) \ W/m^2 \\\\I = 1\ * \ 10^(-6) \ W/m^2`

Therefore, the intensity of the sound in W/m² is 1 x 10⁻⁶ W/m².