Question

A local bakary has determined a probability distribution for the number of cheesecakes that they sell in a

given day.
X= #sold 0 5 10 15 20
Probability 0.26 0.46 0.07 ...? 0.16
What is the probability of selling 15 cheesecakes in a given day? I
What is the probability of selling at least 10 cheesecakes?
What is the probability of selling 5 or 15 chassescakes?
What is the probability of selling 25 cheesecakes?
Give the expected number of cheesecakes sold in a day using the discrete probability distribution?
What is the probability of selling at most 10 cheesecakes?

Answer 1

0.05 ; 0.28 ;0.51 ; 0 ; 6.95 ; 0.79

Step-by-step explanation:

Given tbe probability distribution :

X= #sold_______0 ___5___ 10___ 15___ 20

Probability_P(x) 0.26_ 0.46 _0.07_ ...? ___0.16

A.) probability of selling 15 cheesecakes in a given day;

Sum of P(x) should add up to 1

ΣP(X) = 1

ΣP(X) = (0.26 + 0.46 + 0.07 + x + 0.16) = 1

x = 1 - 0.95

x = 0.05

B.) What is the probability of selling at least 10 cheesecakes?

P(x = 10) + P(x = 15) + P(x = 20)

0.07 + 0.05 + 0.16 = 0.28

C.) What is the probability of selling 5 or 15 chassescakes?

P(x =5) + P(x = 15)

0.46 + 0.05 = 0.51

D.) What is the probability of selling 25 cheesecakes?

Number of cheesecakes sold does not exceed 20`;

p(x = 25) = 0

E.) Give the expected number of cheesecakes sold in a day using the discrete probability distribution?

Σ(X * P(X))

(0.26 * 0) + (0.46 * 5) + (0.07 * 10) + (0.05 * 15) + (0.16 * 20) = 6.95

What is the probability of selling at most 10 cheesecakes?

P(x = 0) + P(x = 5) + P(x = 10)

0.26 + 0.46 + 0.07 = 0.79