212k views
4 votes
The height of a rocket x seconds after it is launched from a hill that is 224 feet high is modeled by the function f (x) = -16x² + 80x + 224.

How long does it take the rocket to hit the ground?
It takes (?) seconds.​
need asap thank you

User Hoeni
by
8.2k points

1 Answer

2 votes

Answer:

t = 7 seconds

Explanation:

The height of a rocket x seconds after it is launched from a hill that is 224 feet high is modeled by the function :

f (x) = -16x² + 80x + 224

We need to find how long does it take the rocket to hit the ground. At that point,

f(x) = 0


-16x^2 + 80x + 224=0\\\\(-16x^2)/(16)+(80x)/(16)+(224)/(16)=0\\\\-x^2+5x+14=0\\\\-x^2+(7-2)x+14=0\\\\-x^2+7x-2x+14=0\\\\x(-x+7)+2(-x+7)=0\\\\(x+2)(-x+7)=0\\\\x=-2\ \text{and}\ x=7

Neglecting -2. Hence, the rocket will take 7 seconds to hit the ground.

User Piyush Sonigra
by
9.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories