Question

5. What is the minimum force required to move a 50 kg steel slab sitting at rest on a steel floor?​

Answer 1

490.5N

Step-by-step explanation:

Step one:

given data

We are told that the mass is 50kg

m= 50kg

From Isaac Newton's first law of motion

F=ma

assuming a= 9.81m/s^2

Substituting we have

F=50*9.81

F= 490.5N

Hence the minimum force required to move the slab is

490.5N