Question

Solve the system of linear equations by substitution. Check your solution.

Answer 1

y = -2

x = 3

Explanation:

First plug in the y= x-5 equation into the 3y = -2x so that it looks like this:

3(x-5)=-2x

Second after distributing the 3 to the x and -5 you will have an equation that looks like this: 3x -15 = -2x

Then you have keep the x's on one side so you add 2x to both sides and add 15 as well so now you have: 5x = 15

Divide both sides by 5 and get x = 3

To find y, you plug x=3 in in to the y = x-5 and get that y = -2

Answer 2

(3, -2)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Equality Properties

Algebra I

• Solving systems of equations using substitution/elimination

Explanation:

Step 1: Define Systems

3y = -2x

y = x - 5

Step 2: Solve for x

Substitution

1. Substitute in y: 3(x - 5) = -2x
2. Distribute 3: 3x - 15 = -2x
3. Add 2x on both sides: 5x - 15 = 0
4. Add 15 on both sides: 5x = 15
5. Divide 5 on both sides: x = 3

Step 3: Solve for y

1. Define equation: y = x - 5
2. Substitute in x: y = 3 - 5
3. Subtract: y = -2