Answer:
0.70631
Explanation:
Given that :
Mean (m) = 20 km
Standard deviation (s) = 6 km
Probability that car travels between 15 and 28 km
Using the relation to obtain the standardized score (Z) :
p(x < 15)
Z = (x - m) / s
Z = (15 - 20) / 6
= - 0.8333
p(Z < - 0.833) = 0.20242 ( Z probability calculator)
(x < 28)
Z = (x - m) / s
Z = (28 - 20) / 6
= 1.333
p(Z < 1.333) = 0.90873 ( Z probability calculator)
0.90873 - 0.20242 = 0.70631