Answer:
![Probability = (1)/(6)](https://img.qammunity.org/2021/formulas/mathematics/college/oj1goldaec65od0w3lvsgwdkxcysit8b93.png)
Explanation:
Given
The above table
Required
Determine the probability of a sum that is a multiple of 6
Represent the event that an outcome is a multiple of 6 with M.
List out all possible values of M
![M = \{6,6,6,6,6,12\}](https://img.qammunity.org/2021/formulas/mathematics/college/s8lhcl19f5rlyuad1lk8xhq9z1p8tcjbrn.png)
Number of M is
![n(M) = 6](https://img.qammunity.org/2021/formulas/mathematics/college/nkeq65r2g9vqr3fuljoeyqdl2vxkjjic3r.png)
Total possible outcome is:
![n(Total) = 36](https://img.qammunity.org/2021/formulas/mathematics/college/ds6hb5i1wr9k42ogjrx3chrs8szk8tuvuo.png)
The theoretical probability is then calculated as follows:
![Probability = (Number\ of\ desired\ outcomes)/(Number\ of\ possible\ outcomes)](https://img.qammunity.org/2021/formulas/mathematics/college/r2x6gb8th0cpq87t7on01foy4cu3942fsi.png)
In this case, it is:
![Probability = (n(M))/(n(Total))](https://img.qammunity.org/2021/formulas/mathematics/college/qxjb6fo7esvex195eep8hrledirwud2rc8.png)
![Probability = (6)/(36)](https://img.qammunity.org/2021/formulas/mathematics/college/r38wksdphyqym35dhazjpsk176ty0qomzd.png)
Simplify fraction
![Probability = (1)/(6)](https://img.qammunity.org/2021/formulas/mathematics/college/oj1goldaec65od0w3lvsgwdkxcysit8b93.png)