Question

Find the equation of the line passing
through the points (3, -2) and (4, 6).
y=[?x +[]

Answer 1

The line equation : y=8x-26

Further explanation

Given

The points (3, -2) and (4, 6)

Required

Line equation

Solution

General formula

y-y1 = m(x-x1)

or

y = mx + c

Where

m = straight-line gradient which is the slope of the line

x1, y1 = the Cartesian coordinate that is crossed by the line

c = constant

The formula for a gradient (m) between 2 points in a line

m = Δy / Δx

Input given values in formula :

(3, -2⇒)x1, y1

(4, 6)⇒x2, y2

`\tt y-(-2)=(6-(-2))/((4-3))(x-3)\\\\y+2=8(x-3)\\\\y=8x-24-2\\\\y=8x-26`