Question

Help!! Thank you so much!!

Answer 1

The volume we're looking for is the volume of both cones in the figure.

The volume of a cone is
`V=\pi r^2(h)/(3)` .

So,
`V_(tot) = V_(1) + V_2` .

Cone 1's variables:

r = 2.6

h = 5

Cone 2's variables:

r = 2.6

h = 3

Now we can just plug and chug!

`V_(tot) = [(3.14)(2.6^2)((5)/(3) )] + [(3.14)(2.6^2)(3)/(3) )]\\V_(tot) = [(3.14)(6.76)(1.67)] + [(3.14)(6.76)(1)]\\V_(tot) = (35.45) + (21.23)\\V_(tot) = 56.68`

V = c. 56.6 cubic units