Question

Write code which takes two inputs from the user, a number of sides followed by a side length, then creates a regular polygon with that number of sides and side length.Sample run:Type the number of sides:8Type a side length:7.5regular octagon with side length 7.5Hint: Make sure you use the right data types when taking user input.

Answer 1

import java.util.Scanner;

public class Polygon {

public static void main(String[] args) {

Scanner sc = new Scanner(System.in);

System.out.println("Type the number of sides:");

int sides = sc.nextInt();

System.out.println("Type a side length:");

double length = sc.nextDouble();

if (sides== 5){

System.out.println("Pentagon, length "+length);

} else if (sides == 6){

System.out.println("Hexagon, length "+length);

} else if (sides == 7){

System.out.println("Heptagon length "+length);

} else if (sides == 8){

System.out.println("Octagon, length "+length);

} else if (sides == 9){

System.out.println("Nonagon, length "+length);

} else if (sides == 10){

System.out.println("Decagon, length "+length);

} else if (sides == 11){

System.out.println("Undecagon, length "+length);

} else if (sides == 12){

System.out.println("Dodecagon, length "+length);

} else {

System.out.println("Please choose a valid number.");

}

}

}

Step-by-step explanation:

The Java source code defines a class called 'Polygon' the main method of the class prompts for user inputs for the sides and length variables. The nested if-statement prints the type of polygon with respect to the number of sides.