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What is the 32nd term of 311, 305, 299

User Sanyassh
by
5.8k points

2 Answers

3 votes

Answer:

503

Explanation:

For an arithmetic sequence, the n-th term is found by


a_n = a_1 + (n - 1)d

To find
d (the common difference) we can simply subtract one of the terms by the last, for example:


d = 299 - 305 \\d = -6 \\

The common difference must be the same throughout the entire sequence, so we can do it once more just to be sure:


d = 305 - 311\\d = -6

We also have to know that
a_1 stands for the first term of the sequence, which in this case is 311.

Now that we know this, let's find the 32nd term


a_(32) = 311 + (32 - 1)-6\\a_(32) = 311 + 192\\a_(32) = 503

Good luck!

User HasilT
by
6.6k points
5 votes

Answer:


a_(32) = 125

Explanation:

d = - 6


a_(n) =
a_(1) + (n - 1)d


a_(32) = 311 + (32 - 1)( - 6) = 125

User Hktang
by
5.8k points