Question

What’s the answer for this question which i have posted can I know the answers as possible

Answer 1

The change in internal energy = 2.701 x 10² kJ

Further explanation

Given

Heat absorbed by system = 1.69 x 10² kJ

Work done on system = 1.011 x 10² kJ

Required

The change in Internal energy

Solution

We can use the first law of Thermodynamics :

`\tt \Delta U=Q+W`

The sign rules for heat and work are set as follows:

• The system receives heat, Q +

• The system releases heat, Q -

• The system does work, W -

• the system accepts work, W +

Heat absorbed/receive heat from surrounding = Q+

Work done on the system = W+

and input the given values

`\tt \Delta U= 1.69* 10^2+1.011* 10^2\\\\\Delta U=\boxed{\bold{2.701* 10^2~kJ}}`