Answer:
1141
7.2
Step-by-step explanation:
The evaporator Temperature T1 = -10°C
h1 = 244.55kj/kg
S1 = 0.93782kj/kg
The enthalpy at second state from given condenser pressure from super heated refrigerant table
P2 = 600
S2 = S1
h2 = 267.19kj/kg
Enthalpy at 3 and 4 from condenser pressure
h3 = h4 = 81.5kj/kg
To get cooling load
QL = m(h1-h4)
M= 7
= 7(244.55-81.5)
= 7(163.05)
= 1141.35kw = 1141KW
COP
= h1-h4/h2 -h1
= 244.55-81.5/267.19-244.55
= 163.05/22.64
= 7.2