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How many oxygen atoms are in 3.14 mol of A1203?

1 Answer

6 votes

Answer:

5.67 × 10²⁴ atoms O

General Formulas and Concepts:

Chemistry - Atomic Structure

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Step-by-step explanation:

Step 1: Define

3.14 mol Al₂O₃

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert


3.14 \ mol \ Al_2O_3((3 \ mol \ O)/(1 \ mol \ Al_2O_3) )((6.022 \cdot 10^(23) \ atoms \ O)/(1 \ mol \ O) ) = 5.67272 × 10²⁴ atoms O

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

5.67272 × 10²⁴ atoms O ≈ 5.67 × 10²⁴ atoms O

User Jarrett Mattson
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