Question

A hockey puck with a mass of 0.18 kg is at rest on the horizontal frictionless surface of the rink. A player applies a horizontal force to the puck which causes it to travel 1.25 meters in 5 seconds. What net force is exerted on the puck?

Answer 1

Hello!

`\large\boxed{0.018 N}`

Begin by finding the acceleration of the puck. Use the kinematic equation:

`d = v_(i) + (1)/(2)at^(2)`

The initial velocity is 0 m/s since the object was at rest, so we can rewrite the equation as:

`d = (1)/(2)at^(2)`

Plug in the given distance and time:

`1.25 = (1)/(2)a(5^(2))\\\\2.50 = 25a\\\\a = 0.1 m/s^(2)`

Find the net force using the formula F = m · a (Newton's Second Law)

F = 0.18 · 0.1

F = 0.018 N