Answer: d) The atomic number decreases by 2
Step-by-step explanation:
A particle alpha is He(2+)
Where we have:
A = 4
Z = 2
The atomic number, the number of protons, must be conserved:
At the beginning (before the emission) we have Z protons.
After the emission, we will have an element with an atomic number X , and an alpha particle with an atomic number = 2.
Then the total number of protons after the emission is X + 2.
The conservation equation is:
Z = X + 2
Isolating X we get:
X = Z - 2
Then after the emission, the atomic number is decreased by 2.
The correct option will be:
d) The atomic number decreases by 2