Question

Consider a system with sampling rate 52,500 samples per second.

(a) Determinethe maximum frequency of the pre-sampled signal if the system utilizes 18% oversampling.
(b) Determine the percentage oversampling if the maximum frequency from part (a) isincreased by 10%.

Answer 1

The answer is "
`22,246 \ H_z \ \ and \ \ 7.3\%`"

Explanation:

The sampling rate:
`(f_s) = 52,500 \ (samples)/(sec)`

In point a:

The sample signal frequency = f

They recognize that the id
`\geq` 2f sampling frequency could be returned to its original signal unless the aliase effect is detected elsewhere, Yet under percentage =18%

`\ sampling \ rate = 2 * 1.18 * f`

`\to f = (52,500)/(2 * 1.18)\\\\`

`= 22,246 \ h_z`

In point b:

Maximum 22,242 frequency is increased by
`10 \ \%`

`f_a =22,246 * 1.1`

`= 24,470.6\\\\=24,471`

`\ sampling \ rate= x * 2 * 24,2471 \\`

`x= (52,500)/(48,942) \\\\x= 1.073\\\\`

over sampling percentage
`= 7.3 \ \%`