Question

What mass of anhydrous copper (II) sulfate can be obtained by the heating of 125.00 grams of copper (II) sulfate pentahydrate?

Answer 1

79.91 g

Step-by-step explanation:

First we calculate the number of moles of 125.00 grams of copper (II) sulfate pentahydrate (CuSO₄·5H₂O), using its molar mass:

• Molar Mass of CuSO₄·5H₂O = (Molar Mass of CuSO₄) + 5*(Molar Mass of H₂O)

• Molar Mass of CuSO₄·5H₂O = 249.68 g/mol

• moles CuSO₄·5H₂O = 125.00 g ÷ 249.68 g/mol = 0.501 mol CuSO₄·5H₂O

In the reaction, CuSO₄·5H₂O turns into CuSO₄.

So now we convert 0.501 moles of CuSO₄ (anhydrous copper (II) sulfate) into grams, using the molar mass of CuSO₄:

• 0.501 mol CuSO₄ * 159.609 g/mol = 79.91 g CuSO₄