Answer: 116 g of copper
Step-by-step explanation:
![Q=I* t](https://img.qammunity.org/2021/formulas/chemistry/high-school/1joxirr85lo88euljsv6emzep33zktweqv.png)
where Q= quantity of electricity in coloumbs
I = current in amperes = 24.5A
t= time in seconds = 4.00 hr =
(1hr=3600s)
![Q=24.5A* 14400s=352800C](https://img.qammunity.org/2021/formulas/chemistry/college/c2uwr8ovlfgkgrku0ryn7dbxgcl2q0h0ee.png)
of electricity deposits 63.5 g of copper.
352800 C of electricity deposits =
of copper.
Thus 116 g of Cu(s) is electroplated by running 24.5A of current
Thus remaining in solution = (0.1-0.003)=0.097moles