Question

The probability that Junkins Food launches a new product in November is 55%. The probability that the director of new products plans a vacation in November is 8.3%. If these events are independent, what is the probability that the director of new products is on vacation when a new product launches in November?

Answer 1

`Probability = 0.04565`

Explanation:

Given

Represent the event that the new product launched in November with N

Represent the event that the director plans a vacation in November with V

Such that

`P(N) = 55\%`

`P(V) = 8.3\%`

Since N and V are independent events.

The required probability is calculated as follows;

`Probability = P(N) * P(V)`

`Probability = 55\% * 8.3\%`

Convert to decimals

`Probability = 0.55 * 0.083`

`Probability = 0.04565`

Hence, the required probability is 0.04565