52.9k views
3 votes
Suppose that you have 12 identical balls and 3 empty boxes. You randomly put every ball into some box. What is the probability that none of the boxes have more than 6 balls?

1 Answer

2 votes

Answer:

the probability that none of the boxes have more than 6 balls is 0.3077

Explanation:

Given that;

12 balls are put into 3 boxes randomly, without ay condition

so we will be using the multinomial formula;

⇒ [ 12 + 3 - 1 [ 14

3 - 1 ] = 2 ] = 91

now, assuming that one of the box has more than 6 balls that is at least 7 balls

x + y + z = 12

x + y + z = 7

therefore

x + 7 + y + z = 12

x + y + z = 5

therefore the number of the solution here computed as;

⇒ [ 5 + 3 - 1 [ 7

3 - 1 ] = 2 ] = 21

Hence, the probability that none of the boxes have more than six (6) balls will be;

= (91 - (3 × 21)) / 91

= (91 - 63) / 91

= 28 / 91

= 0.3077

Therefore the probability that none of the boxes have more than 6 balls is 0.3077

User AttemptedMastery
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories