Answer:
The correct answer would be - high intercellular ratio the ratio of NAD/NADH and low intercellular ratio the ratio of [NADP+]/[NADPH]
Step-by-step explanation:
The role of NAD/NADH in dehydrogenation reactions and NADPH/NADP in reductions explains that to promote or increase the oxidation of substrates the ration of NAD+/NADH should be high:
malate + NAD+ <===-> OAA +NADH + H+.
As NADPH and NADP+ generally help to increase the reduction of substrates, so we expect the ratio of [NADP+]/[NADPH] to low.