Can someone please help me

Question

asked Dec 2, 2023 39.6k views

1 Answer

Eggplant · Answer 1 · 2023-12-06T10:37:46+0000

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \: f(0) = -3$

$\qquad \tt \rightarrow \: f(2) = 1$

$\qquad \tt \rightarrow \: f(4) = 1$

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$\large \tt Solution \: :$

F(x) represents the value of y on curve for given value of x

$\textsf{\large First -}$

$\qquad \tt \rightarrow \: f(0) =( 0) {}^(2) - 3$

[ since 0 < 2 ]

$\qquad \tt \rightarrow \: f(0) = 0 {}^{} - 3$

$\qquad \tt \rightarrow \: f(0) = - 3$

$\textsf{\large Second}$

$\qquad \tt \rightarrow \: f(2) = (2) {}^(2) - 3$

[ since 2 = 2 ]

$\qquad \tt \rightarrow \: f(2) = 4{}^{} - 3$

$\qquad \tt \rightarrow \: f(2) = 1$

$\textsf{\large Third -}$

$\qquad \tt \rightarrow \: f(4) = - 4 + 5$

[ since 4 > 2 ]

$\qquad \tt \rightarrow \: f(4) = 1$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞