Solution :
It is given that dilute hydrochloric acid is titrated with sodium carbonate solution.
of a 0.100
of hydrocholric acid is used.
Thus, 10 mL of the 0.1 molar dilute hydrochloric acid is titrated with 16.2 mL of Sodium carbonate solution.
The equation would be :
Now we know that that the
Molarity =

For hydrochloric acid solution,

∴ n = 0.01 moles.
Now for one mole of
, two moles of HCl acid is used.
For one mole of HCl, one-half mole of
is required.
Therefore, for 0.01 mole of HCl, we require 0.005 mole of
.
Hence, 0.01 mole of hydrochloric acid and 0.005 mole of
solution is used.
The color turns red when methyl orange indicator is used in HCl acid.