Question

Surface area what the surface area of a rectangle 8in 10 3/4ths and 5 1/2

Answer 1

The surface area of the cuboid is 378
`(1)/(4)` square inches.

Explanation:

A cuboid is a shape which has six surfaces formed from a rectangle. The surface area of a cuboid is the sum of all its individual ares of each surface.

Given the following dimensions of the cuboid:

length = 10 3/4 in =
`(43)/(4)` in

width = 8 in

height = 5 1/2 in =
`(11)/(2)` in

Since the opposite surface of a cuboid are the same, then;

Area of the 1st surface = length x width

=
`(43)/(4)` x 8

= 86 square inches

Area of the 2nd surface = width x height

= 8 x
`(11)/(2)`

= 44 square inches

Area of the 3rd surface = length x height

=
`(43)/(4)` x
`(11)/(2)`

=
`(473)/(8)`

= 59
`(1)/(8)` square inches

Surface area of the cuboid = 2 x 86 + 2 x 44 + 2 x
`(473)/(8)`

= 172 + 88 + 118.25

= 378.25

Surface area of the cuboid = 378
`(1)/(4)` square inches