Question

What is the intercept of the line with this equation 8x - 1/3y

= 67
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10)

Answer 1

Given:

The equation is

`8x-(1)/(3)y=67`

To find:

The intercepts of the line.

Solution:

We have,

`8x-(1)/(3)y=67`

Putting x=0, we get

`8(0)-(1)/(3)y=67`

`0-(1)/(3)y=67`

`-(1)/(3)y=67`

Multiply both sides by -3.

`y=-201`

So, y-intercept is -201.

Putting y=0 in given equation, we get

`8x-(1)/(3)(0)=67`

`8x+0=67`

`8x=67`

Divide both sides by 8.

`x=(67)/(8)`

So, the x-intercept is
`x=(67)/(8)`.