Question

A bowling ball of mass 10.2 kg moves in a

straight line at 3.03 m/s.
How fast must a Ping-Pong ball of mass
3.309 g move in a straight line so that the two
balls have the same momentum?
Answer in units of m/s.

Answer 1

v = 9341.19 [m/s]

Step-by-step explanation:

Linear momentum is defined as the product of mass by Velocity. In this way by means of the following equation, we can calculate the momentum.

`P=m*v`

where:

P = momentum [kg*m/s]

m = mass = 10.2[kg]

v = velocity = 3.03 [m/s]

Now replacing, we have:

`P=10.2*3.03\\P = 30.91 [kg*m/s]`

Now the ping-pong mass is 3.309 [g] or 0.003309 [kg]

We can clear the value for v from the equation above.

`v = P/m\\v = 30.91/0.003309\\v = 9341.19 [m/s]`