Question

Solid lead(11) carbonate reacts with a dilute solution of

nitric acid (HNO,) to give a solution of lead(II) nitrate,
carbon dioxide and water.

Answer 1

The reaction between solid lead(II) carbonate and nitric acid produces lead(II) nitrate, carbon dioxide, and water, demonstrating how carbonates can form soluble nitrates when reacted with acids.

Step-by-step explanation:

To answer the question, the reaction between solid lead(II) carbonate and dilute nitric acid results in the formation of a lead(II) nitrate solution, carbon dioxide (CO2), and water (H2O). This is a chemical reaction that involves the decomposition of solid lead(II) carbonate when it comes into contact with an acid, producing soluble lead(II) nitrate, which is a characteristic property of most nitrates being soluble in water. It's noteworthy that this type of reaction is commonly used to prepare soluble metal nitrates from carbonates.

Answer 2

PbCO₃ + 2HNO₃ –> Pb(NO₃)₂ + CO₂ + H₂O

Step-by-step explanation:

From the question given above:

Solid lead (II) carbonate reacts with a dilute solution of nitric acid (HNO₃) to give a solution of lead (II) nitrate,

carbon dioxide and water.

The above can be represented in the equation form as follow:

PbCO₃ + HNO₃ –> Pb(NO₃)₂ + CO₂ + H₂O

Finally, we shall balance the equation as follow:

PbCO₃ + HNO₃ –> Pb(NO₃)₂ + CO₂ + H₂O

There are 2 atoms of H on the right side and 1 atom on the left side. It can be balance by putting 2 in front of HNO₃ as shown below:

PbCO₃ + 2HNO₃ –> Pb(NO₃)₂ + CO₂ + H₂O

Now, the equation is balanced.