Question

The hydrogen emission spectrum is shown below. What is the energy of the

410 nm emission line? (The speed of light in a vacuum is 3.00 x 108 m/s, and
Planck's constant is 6.626 x 10-34 J.s.)
400
750 pm

Answer 1

C.) 4.85 x 10⁻¹⁹ J

Step-by-step explanation:

To find the energy, you need to use the following equation:

E = hc / w

In this formula,

-----> E = energy (J)

-----> h = Planck's Constant (6.626 x 10⁻³⁴ J*s)

-----> c = speed of light (3.00 x 10⁸ m/s)

-----> w = wavelength (m)

Once you have converted nanometers to meters, you can plug the given values into the equation and solve.

410 nm 1 m
------------- x ---------------------- = 4.10 x 10⁻⁷ m
1 x 10⁹ nm

E = hc / w

E = (6.626 x 10⁻³⁴ J*s)(3.00 x 10⁸ m/s) / (4.10 x 10⁻⁷ m)

E = 4.85 x 10⁻¹⁹ J