Answer:
A.) T = 1.25s
B.) H = 7.7m
Step-by-step explanation:
Given that a football is kicked at 55o at 15 m/s.
How long is it in the air?
Let's use the formula below:
V = UsinØ - gt
V = 0 at maximum height.
0 = UsinØ - gt
UsinØ = gt
Substitute all the parameters into the formula
15sin55 = 9.8t
9.8t = 12.29
t = 12.29/9.8
t = 1.25 seconds
How far does it travel to go through the is at the same height as when it started?
That will be the maximum height.
Using the third equation of motion
V^2 = U^2 sin^2ø - 2gH
At maximum height, V = 0
(UsinØ)^2 = 2gH
(15sin55)^2 = 2 × 9.8H
(12.29)^2 = 19.6H
H = 150.97/19.6
H = 7.7 m