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Find the range of the function for the domain {−3, 1, 4.5}. f(x) = 2x^2

Find the range of the function for the domain {−3, 1, 4.5}. f(x) = 2x^2-example-1

2 Answers

4 votes

Answer:

D.

Explanation:

The domain can be understood as being the x whereas the y can be considered as being the range.

We know that in order to find the y, or in order words
f(x) we can simply plug in any x value that we're interested in into
f(x) = 2x^(2)

If we do that with the values of x (or domain) that we have from the problem, we will get


f(-3) = 2\cdot (-3)^2 \\f(-3) = 18\\\\f(1) = 2\cdot 1^2\\f(1) = 2\\\\f(4.5) = 2\cdot 4.5^2\\f(4.5) = 40.5\\

From the results that we got, we know that the answer is D.

Good luck!

User Benjamin Breton
by
8.4k points
2 votes

Answer:

D

Explanation:

f(x) = 2x^2

f(3) = 2*(-3)^2

f(3) = 2* 9

f(3) = 18

=======

f(1) = 2*(1)^2

f(1) = 2*1

f(1) = 2

=========

f(4.5) = 2*4.5^2

f(4.5) = 2 * 20.25

f(4.5) = 40.5

============

D

User Manish Nagar
by
8.7k points

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