Question

There is a 90 kg woman attached at the end of a bungee cord (k = 35 N/m) that is experiencing simple harmonic motion. How long does it take the woman to complete one cycle?

Answer 1

The value is
`T =10.1 \ s`

Step-by-step explanation:

From the question we are told that

The mass of the woman is
`m = 90 \ kg`

The spring constant of the bungee cord is
`k = 35 \ N/ m`

Generally the period of the oscillation (i,e time taken to complete on cycle ) is mathematically represented as

`T = 2 \pi * \sqrt{ (m)/(k) }`

=>
`T = 2 * 3.142 * \sqrt{ (90 )/( 35) }`

=>
`T =10.1 \ s`