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N₂ + 3H2 → 2NH3

224 L of nitrogen reacts with
excess hydrogen at 2773 K and
95 atm, using up 93.5 mol N2.
How many moles of ammonia
form?

N₂ + 3H2 → 2NH3 224 L of nitrogen reacts with excess hydrogen at 2773 K and 95 atm-example-1
User Deebster
by
2.9k points

1 Answer

9 votes

Answer:

187 moles NH₃

Step-by-step explanation:

To find the amount of ammonia formed, you need to multiply the given value by the mole-to-mole ratio consisting of both relevant molecules. The mole-to-mole ratio is made up of the molecules' coefficients in the balanced equation. The desired unit should be placed in the numerator of the ratio. The final answer should have 3 sig figs to reflect the lowest amount of sig figs among the given values.

1 N₂ + 3 H₂ ----> 2 NH₃
^ ^

93.5 moles N₂ 2 moles NH₃
---------------------- x ------------------------- = 187 moles NH
1 mole N₂

User Yibin Lin
by
3.2k points