Question

Find the y-intercept for the parabola defined by

this equation:
y=6x2 – 10x +4
separate the values with a comma

Answer 1

The y intercept is at (0, 4)

Explanation:

The y-intercept happens when the curve reaches an x-coordinate of zero. Because this is a quadratic expression, we know that it is a proper parabolic function, and will have a single y-intercept:

`y = 6x^2 - 10x + 4\\y = 6(0)^2 - 10(0) + 4\\y = 4`

So the y intercept for this function is at (0, 4)