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Anyone question 8 pleaseeeeeeeeeee

Anyone question 8 pleaseeeeeeeeeee-example-1
User Dpassage
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1 Answer

4 votes

Answer:

$200 and $450

Explanation:

We can start by assigning variables to our unknowns.

Our unknowns are the price for a DVD player and the price for a television.

x= price of a television

y= price of a DVD player

Next, let's translate the given information into a system of equations.

two televisions and three DVD players for $1750

2x+3y=1750

four televisions and one DVD player for $1250

4x+y=1250

Since the instructions did not specify, I will use substitution to solve, however you can also use elimination.

First, from the second equation, we subtract 4x from both sides.

4x+y-4x=1250-4x

y=1250-4x

Now we plug 1250-4x for y in the first equation.

2x+3y=1750

2x+3(1250-4x)=1750

Distribute.

2x+3*1250-3*4x=1750

Simplify.

2x+3750-12x=1750

Combine like terms.

-10x+3750=1750

Subtract 3750 from both sides

-10x+3750-3750=1750-3750

-10x=-2000

Divide both sides by -10

x=200

A television costs $200.

Now using that, we can plug that into one of the original equations. I'll use the second one.

4x+y=1250

4(200)+y=1250

800+y=1250

Subtract 800 from both sides.

y=450

A DVD player costs $450

You can plug those values back into the other equation (the first one) to double-check if you'd like as well.

User Try Catch Finally
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