Question

The equation of line q is 5y - 4x = 10. Write the standard fom of the equation of the line that fits the following description:

parallel to q and passes through the point at (-15, 8)

Answer 1

Answer: -4x+5y = 100

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Step-by-step explanation:

The given equation is the same as -4x+5y = 10

It is of the form Ax+By = C, where A = -4, B = 5, C = 10

Anything parallel to Ax+By = C is of the form Ax+By = D. The only difference is the C has changed to a D.

This means anything parallel to -4x+5y = 10 is -4x+5y = D, where D is not equal to 10, but it could be any other number.

Plug in the coordinates of (-15,8) to find the value of D

-4x+5y = D

-4(-15)+5(8) = D

60+40 = D

100 = D

D = 100

We have -4x+5y = D update to -4x+5y = 100

The equation -4x+5y = 100 is parallel to -4x+5y = 10, and it goes through (-15,8)

Parallel lines have the same slope, but different y intercepts.

Note how Ax+By = C has a slope of m = -B/A. This means A cannot be zero.