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What is the value of x for which (8-x)^2=x^2

2 Answers

3 votes

Explanation:

(8 - x)² = x²

=> 8 - x = x or 8 - x = -x (rejected)

=> x = 4.

User Melegant
by
7.6k points
1 vote

Answer:

x = 4

Explanation:


{x}^(2) = {(8 - x)}^(2)


= > {x}^(2) = {x}^(2) - 16x + 64


= > {x}^(2) - {x}^(2) + 16x = 64


= > 16x = 64


= > x = (64)/(16) = 4

User Jamesrom
by
7.5k points