Question

A particle is moving along the number line so that its distance (in meters) from the origin at any time t (in seconds) is given by s(t) = 8t2 + ln t.

The velocity of the particle at t = 1 second is:

Answer 1

The velocity is 17 m/s

Explanation:

To find the velocity, we find the first differential of the displacement

That will be

S’(t) = 16t + 1/t

We simply proceed to replace t with 1

That will give;

16(1) + 1/1

= 16 + 1 = 17 m/s