Question

Find the area A of triangle JKL with the vertices J(5,8), K(0,7), and L(5,4)

Answer 1

Area of the triangle is 10 square units

Explanation:

Recall that the formula for the area of a triangle is: "base x height / 2", and in this case, we can consider the triangle's base as the segment that joins the vertices (5, 4) and (5, 8) which gives a segment length of 4 units. The height of the triangle is then the distance between the third vertex (0,7) and the base, which is exactly 5 units. Then the area becomes:

Area = 4 x 5 / 2 = 10 square units.