Question

How many moles of O2 are needed to burn 2.56 moles of CH3OH?

Answer 1

`n_(O_2)=3.84molO_2`

Step-by-step explanation:

Hello!

In this case, since the combustion reaction of methanol is:

`CH_3OH+(3)/(2) O_2\rightarrow CO_2+2H_2O`

In such a way, since there is 1:3/2 mole ratio between methanol and oxygen, we can compute the moles of oxygen that are needed to burn 2.56 moles of methanol as shown below:

`n_(O_2)=2.56molCH_3OH*((3)/(2)molO_2)/(1molCH_3OH) \\\\n_(O_2)=3.84molO_2`

Best regards!